(xy+1)(x+1)(y+1)+xy
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(xy+1)(x+1)(y+1)+xy(xy+1)(x+1)(y+1)+xy(xy+1)(x+1)(y+1)+xy(xy+1)(x+1)(y+1)+xy=(xy+1)(xy+1+x+y)+xy=(xy
(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy
=(xy+1)(xy+1+x+y)+xy
=(xy+1)(xy+x+1)+y(xy+1)+xy
=(xy+1)(xy+x+1)+y(xy+1+x)
=(xy+x+1)(xy+y+1)
前两个因式提取xy+1成为（xy+1)(xy+1+x)，后两个提取y成为y(xy+1+x)于是整个式子化成(xy+1)(xy+1+x)+y(xy+1+x),再提取公因式xy+1+x就可以啦。其实这种题多找几个公因式试试就行啦
分不起来
xy-1+x-y
(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy
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