3[x-2(x-1)]=9x怎么做
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3[x-2(x-1)]=9x怎么做3[x-2(x-1)]=9x怎么做3[x-2(x-1)]=9x怎么做两边除以3x-2(x-1)=3xx-2x+2=3x3x-x+2x=24x=2x=2÷4x=1/23
3[x-2(x-1)]=9x怎么做
3[x-2(x-1)]=9x怎么做
3[x-2(x-1)]=9x怎么做
两边除以3
x-2(x-1)=3x
x-2x+2=3x
3x-x+2x=2
4x=2
x=2÷4
x=1/2
3[x-2(x-1)]=9x
3(-x+2)=9x
-3x+6=9x
12x=6
x=1/2
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