若(y-2)+|x-2y|=0,则log4(底数)y=

若log底数2[log底数3(log底数4)]若log底数2[log底数3(log底数4（x）)]=log底数3[log底数4(log底数2(y))]=log底数4[log底数2(log底数3z)]=0,则x+y+z= 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 [log(4)(2x)][log(2x)(3y)][log(3y)(z)]=log(8x)[(8x)]^2,则z=? 2log(m)y-log(m)x-log(m)z log 9 X/Y=1/2(log 3 X - log 3 Y) log 9 X/Y=1/4 3log 3 X =2log 3 Y find X and Y 若-3≤log(1/2)x≤-1/2,则函数y=(log(2)x－1)(log(2)x－2)的值域为? 若x＞0,y＞0,且2log（x-2y）=logx+logy,则x/y等于多少 若log(根号2)x+log(根号2)y≥4,则x+y的最小值是 若log根号下2x+log根号下2y≥4,则x+y的最小值是 怎么画出y=log|x+2|和y=log|x|的图像 英语翻译init:X,Y = 0,.1;endinitY=@log(X);X^2+Y^2 log 3 (4+x+4y)^2=0 联立 log 2 (x+1)^2=1+3log 2 y^2 求 若lgx+lgy=2lg(x-2y),求2log（2,x/y） 已知x^2+y^2-4x-2y+5=0,求log（x）y^x的值 用C语言计算log(5)log(3)-log(2))/sin(π/3)=#include #includeint main(){int a=5,b=3,c=2;double y;y=(log(a)log(b)-log(c))/sin(π/b);printf((log(5)log(3)-log(2))/sin(π/3)=%ld,y);return 0;}x这哪里错了? log(a)(b)=log(b)(a)(a≠1,b≠1,c≠1),则ab=（log(x)(y))^2+(log(y)(x))^2=1,则y可用x表示为前面那个括号是底数 log(4)y+log(2y)=9怎么解 (2x+3y-5)[log(x+2y)-3]=0,则方程所表示的曲线是什么?为什么?