[log(4)(2x)][log(2x)(3y)][log(3y)(z)]=log(8x)[(8x)]^2,则z=?

log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) [( log(x^2) + log(x^4) )/ log(100 x)] = 4 求X log(2)(x)log(2)(4x)-3log(2)(x)-12=0 简化2log (x + 4) – log(2x + 8) + log(x - 2)谢谢~ (log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0 2log(m)y-log(m)x-log(m)z 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 2 log(3x)= log 4 +log(6-x)怎么求...急 已知log(2){log(3)[log(4)(x)]}=5^0,则x=? log(2)(x+4)=3^x 若log底数2[log底数3(log底数4)]若log底数2[log底数3(log底数4（x）)]=log底数3[log底数4(log底数2(y))]=log底数4[log底数2(log底数3z)]=0,则x+y+z= 1/log（2）x+1/log（3）x+1/log（4）x=1,x=? log（x+5）=log（x）+log（2） log（8）+log（x）=log（24） 2log（x）=log(2x)+log(3) 试解关于x的不等式log(2)x+4log(3)x+12log(8)x+n·2^(n-1)·log(2^n)x 对数计算1.{log(4)（3）+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(2)(3)} X {log(3)(4)+log(9)(2)}3.(lg2)^+1g2X 1g5 +1g50 解方程3log(x)4+2log(4x)4+3log(16x)4=0 solve:log(x)+log(2x)=2 解方程：log√x 2x=4log√x 2x=4