3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]
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3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]这是要什么化简
3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]
3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]
3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]
这是要什么 化简?题目你也没说清楚啊 亲
3x2y+xy2-[2xy2-4x2y+(x2y-2xy2)]
5xy2-【3xy2-(4xy2-2x2y)】+2x2y】+2x2y-xy2 化简,再求值
-3x2y+2x2y+3xy2-2xy2
-3x2+2x2y+xy2
(x2y)3 × (-xy2)3
-2x2y(-2xy2)2+(2xy)3×( xy2)
化简:5(3x2y-xy2) * (xy2+3x2y)
4xy2-4x2y-y3 (2 3 是方)
x3-2x2y+xy2-x
因式分解:x3-2x2y+xy2
x.y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3).y取何值时,代数(x3y+3x2y-5xy2+6y3)+(y3+2xy2+x2y-2x3)-(4x2y-x3-3xy2+7y3)的值都是常数?
(4xy2-2x2y)-( )=x3-2x2y+4xy2+y3.
已知:(x+2)2+|y+1|=0,求5xy2-{2x2y-[3xy2-(4xy2-2x2y)]}的值
试说明代数式(x3+3x2y-4xy2+6y3)-(2x3-x2y-xy2-y3-1)+(x34x2y+3xy2-7y3)的值与xy取值无关
4x2y-{x2y-「3xy2 – 1/ 2(4x2y-8xy2)+x2y」}-5xy2 在此题中2是x或y的平方(2次方)
若(x-3)+|y+2|=0,求代数式3x2y-【xy2减2(2xy2减3x2y)+x2y】+4xy2
(6x2y-xy2-1/2x2y3)/(-3xy)
(-1/2x2y)`(-3xy2)=