x+y=4,y+z=3,x+z=-1

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x+y=4,y+z=3,x+z=-1x+y=4,y+z=3,x+z=-1x+y=4,y+z=3,x+z=-1x+y=4,y+z=3,x+z=-1由第一个方程得x=4-y带入第三个方程得4-y+z=-1

x+y=4,y+z=3,x+z=-1
x+y=4,y+z=3,x+z=-1

x+y=4,y+z=3,x+z=-1
x+y=4,
y+z=3
,x+z=-1
由第一个方程得x=4-y带入第三个方程得 4-y+z=-1 即为-y+z=-5
再由第二个方程得y=3-z 带入 -y+z=-5 得-3+z+z=-5 得z=-1
把z=-1带入y=3-z=4 把y=4带入x=4-y=0

三式相加得x+y+z=3再减去1式2式3式分别得出z=-1x=0,y=4

x=0,y=4,z=-1

三式相加可得2(x+y+z)=6
于是x+y+z=3
用它分别与三个式子相减得：
z=-1,x=0,y=4

已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? (x+y-z)(x-y+z)= x+y/2=z+x/3=y+z/4 x+y+z=27 x+2y=3x+2z=4y+z 求x:y:z x,y,z不是0.3z=4y,z=3x求（x+y）：（x+z）. 已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值 x+y+z=6 x+2y+3z=14 y+1=z 已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1 x-y-z=1 2x+y-3z=4 3x-2y-z=-1 x+y+z=2 4x+2y+z=4 2x+3y+z=1 {3X+2Y+Z=4X+Y+Z=102X+3Y-Z=1 x+y-z=6 x-3y+2z=1 3x+2y-z=4 阿 x+y-z=6,x-3y+2z=1,3x+2y-z=4 x+y+z=-5,3x+y+z=1,4x+3y+2z=-2快 3x+2y+z=4 x+y+z=10 2x+3y-z=1