已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则……已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则a=?,b=?,c=?
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已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则……已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则a=?,b=?,c=?已
已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则……已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则a=?,b=?,c=?
已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则……
已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则a=?,b=?,c=?
已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则……已知6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c),则a=?,b=?,c=?
(2x-3y+b)(3x+y+c)
=(2x-3y)(3x+y)+b(3x+y)+c(2x-3y)+bc
=6x^2-7xy-3y^2+(3b+2c)x+(b-3c)y+bc
∵6x^2-7xy-3y^2+14x+y+a=(2x-3y+b)(3x+y+c)
14=3b+2c
1=b-3c
a=bc
∴a=4
b=4
c=1
本题适用待定系数法 等号 右边展开 得到6x^2-7xy-3y^2+(3b+2c)x+(b-3c)y+bc
比较两边系数 的三元一次方程组 1、3b+2c=14;2、b-3c=1;3、bc=a;先解前2个 得到b=4;c=1;代入方程3得a=4; 方法详情 可以参考巨人学校初中数学初二秋季班 讲义
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