5y-4÷2y-4+1÷2=2y+5÷(3y-6)解方程

4y²-4y/y²-2y+1÷(y+1/y-1-y-1/y+1)÷(3y+3) [(x+y)(x-y)-(x-y)²+2y(x-y)]÷4y 5y-4÷2y-4+1÷2=2y+5÷(3y-6)解方程 2(y-4)(3y+2)-5(-3y+7)(y+1),其中y=-1 实数x,y满足|2分之5x-y|+y²-10y+25=0,求代数式1-x-2y分之x-y÷x平方-y平方分之x²-4xy+4y 已知x²+4y²-4x+4y+5=0,求(2x-y)(x+y)/x四次方-y四次方×xy-y²/2x-y÷(y/x²+y²)² y^2-6y-2÷2y-4= [(x-2y)(x+2y)+4(x-y)^2]÷5y 计算y-3/4y-8÷(y+2-5/y-2) y-3/4y-8÷(5/y-2-y-2) 计算` （y-3）/（4y-8）÷（y+2-5/（y-2）） y-3/4y-8÷（5/y-2 -y-2) 一道数学题, 计算.2x÷x/5x+3y^2-4y+4/2y-6·1/y+3÷12-6y/9-y^2 1/2y+1=4y-2/5-y 先化简,再求值[(2x+y)^2-(2x+y)(2x-y)-y(5x+y)]÷(1/2y),其中x-y=2 已知x-y=1,求[(x+2y)²+(2x+y)(x-4y)-3(x+y)(x-y)]÷y的值 2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y y-1/y-2 - y-3/y-4=y-2/y-3 - y-4/y-5一共有四个分数哦~希望可以快一点~谢谢!