已知数列{an}满足a1=0,an+1+sn=n^2+2n已知数列{an}满足a1=0,a(n+1)+sn=n^2+2n(n属于N*),其中Sn为{an}的前n项和,求次数列的通项公式
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已知数列{an}满足a1=0,an+1+sn=n^2+2n已知数列{an}满足a1=0,a(n+1)+sn=n^2+2n(n属于N*),其中Sn为{an}的前n项和,求次数列的通项公式已知数列{an}
已知数列{an}满足a1=0,an+1+sn=n^2+2n已知数列{an}满足a1=0,a(n+1)+sn=n^2+2n(n属于N*),其中Sn为{an}的前n项和,求次数列的通项公式
已知数列{an}满足a1=0,an+1+sn=n^2+2n
已知数列{an}满足a1=0,a(n+1)+sn=n^2+2n(n属于N*),其中Sn为{an}的前n项和,求次数列的通项公式
已知数列{an}满足a1=0,an+1+sn=n^2+2n已知数列{an}满足a1=0,a(n+1)+sn=n^2+2n(n属于N*),其中Sn为{an}的前n项和,求次数列的通项公式
a(n+1)+Sn=S(n+1)=n^2+2n
S(n+1)+1=(n+1)^2
Sn=n^2-1 .(n>1)
S(n+1)-Sn=2n+1=a(n+1)
an=2n-1...(n>1)
an=0...(n=1)
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