已知2x+y÷2=5x+2y÷4=1,求(x+2y+1)÷(2x-3y+7)的值
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已知2x+y÷2=5x+2y÷4=1,求(x+2y+1)÷(2x-3y+7)的值已知2x+y÷2=5x+2y÷4=1,求(x+2y+1)÷(2x-3y+7)的值已知2x+y÷2=5x+2y÷4=1,求
已知2x+y÷2=5x+2y÷4=1,求(x+2y+1)÷(2x-3y+7)的值
已知2x+y÷2=5x+2y÷4=1,求(x+2y+1)÷(2x-3y+7)的值
已知2x+y÷2=5x+2y÷4=1,求(x+2y+1)÷(2x-3y+7)的值
(2x+y)/2=1化2x+y=2 ……(1)
5x+2y÷4=1化5x+2y=4 ……(2)
解1.2方程组得:x=0.y=2
代入(x+2y+1)÷(2x-3y+7)=5
因为你式子表达得不好,我只能这么理解,思路是这样,如果有错误就自己看着办
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