若x/x^2-x+1=6/7,求x^4+x^2+1/x^2
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若x/x^2-x+1=6/7,求x^4+x^2+1/x^2若x/x^2-x+1=6/7,求x^4+x^2+1/x^2若x/x^2-x+1=6/7,求x^4+x^2+1/x^2(x²-x+1)
若x/x^2-x+1=6/7,求x^4+x^2+1/x^2
若x/x^2-x+1=6/7,求x^4+x^2+1/x^2
若x/x^2-x+1=6/7,求x^4+x^2+1/x^2
(x²-x+1)/x=7/6
x -1 +1/x=7/6
∴x+1/x=13/6
两边平方得
x²+2+1/x²=169/36
x²+1+1/x²=133/36
∴（x^4+x^2+1)/x^2=133/36
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