[x(x²y²-xy)-2y(x²-x³y)÷3x²y

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[x(x²y²-xy)-2y(x²-x³y)÷3x²y[x(x²y²-xy)-2y(x²-x³y)÷3x

[x(x²y²-xy)-2y(x²-x³y)÷3x²y
[x(x²y²-xy)-2y(x²-x³y)÷3x²y

[x(x²y²-xy)-2y(x²-x³y)÷3x²y
[x(x²y²-xy)-2y(x²-x³y)]÷3x²y
　= (1/3)[(xy-1)-2(1-xy)]
　= xy-1