An electrical heater is used to supply 160.0 J of energy to a 30.0 g sample of water,originally at 300.0 K. Determine the final temperature in degrees Kelvin.(the specific heat capacity for water is 75.291 Jmol-1K-1)An electrical heater is used to a

An electrical heater is used to supply 160.0 J of energy to a 30.0 g sample of water,originally at 300.0 K. Determine the final temperature in degrees Kelvin.(the specific heat capacity for water is 75.291 Jmol-1K-1)An electrical heater is used to a
An electrical heater is used to supply 160.0 J of energy to a  30.0 g sample of water,originally at 300.0 K. Determine the final temperature in degrees Kelvin.(the specific heat capacity for water is 75.291 Jmol-1K-1)
An electrical heater is used to add 19.50 kJ of heat  to a constant-volume calorimeter. The temperature of the calorimeter  increases by 4.48°C. When 2.25 g  of propanol (C3H7OH) is burned in the same calorimeter,the temperature  increases by 17.38°C. Calculate the molar heat of  combustion for propanol (enter in kJ).
A home swimming pool contains 150 m3 of water. At the beginning of the swimming season,the water must be heated from 15 to 28°C.How many joules of heat energy must be supplied?
Suppose 100.0 mL of 1.50 M HCl  and 100.0 mL of 1.50 M NaOH,both  initially at 21.0°C,are mixed in a thermos flask.  When the reaction is complete,the temperature is 31.2°C.  Assuming that the solutions have the same heat capacity as pure water,compute the heat released (in kJ).
A coin dealer,offered a rare silver coin,suspected that it might be a counterfeit nickel copy. The dealer heated the coin,which weighed 17.5 g to 100°C in boiling water and  then dropped the hot coin into 20.5 g of water at T = 16.5°C in  an insulated coffee-cup,and measured the rise in temperature. If the coin was really made of silver, what would the final temperature of the water be (in °C)?(for nickel,s = 0.445 J/g°C; for silver,s = 0.233 J/g°C )
能做出几道做几道,

An electrical heater is used to supply 160.0 J of energy to a 30.0 g sample of water,originally at 300.0 K. Determine the final temperature in degrees Kelvin.(the specific heat capacity for water is 75.291 Jmol-1K-1)An electrical heater is used to a
第一题：30g水即1.67摩尔,利用物理学公式：温度变化=能量×摩尔质量/比热容即可计算得出变化的热力学温度值,再将热力学温度转换到Kelvin温度.
第二题：升温4.48摄氏度需要19.5kJ,可以用等比公式计算出升温17.38摄氏度所需热量,用所得热量值除以2.25g酒精的摩尔质量即可得出答案.
第三题：纯粹物理题,热量=质量×比热容（第一题有）×温度变化
第四题：同第3题,主要问题在于求质量,100mL×1.5mol/L科德其摩尔质量
第五题：
设最终平衡度为x,（x-16.5）×水比热×20.5=（100-x）×银比热×17.5,得出如果是银币的最终温度,再用同一种方法求镍的最终温度,进行比较