If T is the set of even integers and S is the set of integers that are divisible by 7,which of the following integers is NOT contained in set T and is NOT contained in set A 4 B 10C 28D35E39额第一道爆容易我看错题目了。应该是下面这
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/06 02:30:56
If T is the set of even integers and S is the set of integers that are divisible by 7,which of the following integers is NOT contained in set T and is NOT contained in set A 4 B 10C 28D35E39额第一道爆容易我看错题目了。应该是下面这
If T is the set of even integers and S is the set of integers that are divisible by 7,which of the following integers is NOT contained in set T and is NOT contained in set
A 4
B 10
C 28
D35
E39
额第一道爆容易我看错题目了。
应该是下面这道
还有一道
Marsha is making a necklace.She starts with 2 red beads,3 white beads,and 4 blue beads,in that orde,and repeats the pattern until there is no more room on the necklace.If the last bead is white .which of the following coule be the total number of beads on the necklace.
A 80
B 78
C 76
D 74
E 72
If T is the set of even integers and S is the set of integers that are divisible by 7,which of the following integers is NOT contained in set T and is NOT contained in set A 4 B 10C 28D35E39额第一道爆容易我看错题目了。应该是下面这
第一题是问下面那个数既不能被2整除又不能被7整除,答案是39
第二题珠子的颜色是9个一循环.白色的珠子号码只能是除9余3,4,5
下面只有76是满足条件的
请教一道SAT数学题~~~~~请教一道SAT数学题~~~~~
T是一个偶数的集合
S是一个能被7整除的集合
问下面哪个数不再集合T 与 S中
那么就是E 39了
连续穿2红3白4蓝 一个循环就是9个 那轮到白色时 珠子的数目就应该是除以9之后 余数为3 4 5的可能性
即答案为C 76谢谢 再问你一个翻译, 我对数学这些运算的翻译有些搞不懂。 if the dealer has twice as ma...
全部展开
T是一个偶数的集合
S是一个能被7整除的集合
问下面哪个数不再集合T 与 S中
那么就是E 39了
连续穿2红3白4蓝 一个循环就是9个 那轮到白色时 珠子的数目就应该是除以9之后 余数为3 4 5的可能性
即答案为C 76
收起