因式分解：①4(3p+5q)^2-9(2p-q)^2 ②2(x+y)^3-8(x+y) ）
来源：学生作业帮助网 编辑：六六作业网 时间：2024/12/19 14:51:07
因式分解：①4(3p+5q)^2-9(2p-q)^2 ②2(x+y)^3-8(x+y) ）
因式分解：①4(3p+5q)^2-9(2p-q)^2 ②2(x+y)^3-8(x+y) ）
因式分解：①4(3p+5q)^2-9(2p-q)^2 ②2(x+y)^3-8(x+y) ）
：①4(3p+5q)^2-9(2p-q)^2
=[2(3p+5q)]²-[3(2p-q)]²
=(6p+10q)²-(6p-3q)²
=(6p+10q+6p-3q)(6p+10q-6p+3q)
=(12p+7q)*13q
=13p(12p+7q)
：①4(3p+5q)^2-9(2p-q)^2
=4(9p²+30pq+25q²)-9(4p²-4pq+q²)
=36p²+120pq+100q²-36p²+36pq-9q²
=156pq+91q²
=13q(12p+7q)
②2(x+y)^3-8(x+y)
=[2(x+y)][(x+y)²-4]
=2(x+y)(x+y+2)(x+y-2)
①4(3p+5q)^2-9(2p-q)^2
=[2(3p+5q)]^2-[3(2p-q)]^2
=[2(3p+5q)+3(2p-q)][2(3p+5q)-3(2p-q)]
=(6p+10q+6p-3q)(6p+10q-6p+3q)
=13q(12p+7q)
②2(x+y)^3-8(x+y)
=2(x+y)[(x+y)^2-4]
=2(x+y)(x+y+2)(x+y-2)
4(3p+5q)^2-9(2p-q)^2
=[2(3p+5q)+3(2p-q)][2(3p+5q)-3(2p-q)]
=(6p+10q+6p-3q)(6p+10q-6p+3q)
=13q(12p+7q)
.（2(x-y)^3-8(x-y）
=2(x-y)[(x-y)^2-4]
=2(x-y)(x-y-2）（x-y+2)
4(3p+5q)^2-9(2p-q)^2=(6p+10q)^2 - (6p-3q)^2=[(6p+10q)+(6p-3q)][(6p+10q)-(6p-3q)]
=13q(12p+7q)
2(x+y)^3-8(x+y)=(2x+2y)[(x+y)^2-4]=)=(2x+2y)(x+y-2)(x+y+2)
解4(3p+5q)^2-9(2p-q)^2
=[2(3p+5q)]^2-[3(2p-q)]^2
=[2(3p+5q)-3(2p-q)][2(3p+5q)+3(2p-q)]
=[6p+10q-6p+3q)][6p+10q+6p-3q]
=13q*（12p+7q）
2(x+y)³-8(x+y)
=2(x+y)[(x+y)²-4]
=2(x+y)(x+y+2)(x+y-2)
①4(3p+5q)²-9(2p-q)²
=[2(3p+5q)-3(2p-q)]²
=(13p)²
=169p²
②2(x+y)³-8(x+y)
=2(x+y)[(x+y)²-4]
=2(x+y)(x+y+2)(x+y-2)
<...
全部展开
①4(3p+5q)²-9(2p-q)²
=[2(3p+5q)-3(2p-q)]²
=(13p)²
=169p²
②2(x+y)³-8(x+y)
=2(x+y)[(x+y)²-4]
=2(x+y)(x+y+2)(x+y-2)
很高兴为您解答，祝你学习进步！【学习宝典】团队为您答题。
有不明白的可以追问！如果您认可我的回答。
请点击下面的【选为满意回答】按钮，谢谢！
收起