因式分解(1) y的4次方-y²=6, (2) (y-1)²-6(y+1)=-8(2)(y+1)²-6(y+1)=-8

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因式分解(1)y的4次方-y²=6,(2)(y-1)²-6(y+1)=-8(2)(y+1)²-6(y+1)=-8因式分解(1)y的4次方-y²=6,(2)(y-

因式分解(1) y的4次方-y²=6, (2) (y-1)²-6(y+1)=-8(2)(y+1)²-6(y+1)=-8
因式分解(1) y的4次方-y²=6, (2) (y-1)²-6(y+1)=-8
(2)(y+1)²-6(y+1)=-8

因式分解(1) y的4次方-y²=6, (2) (y-1)²-6(y+1)=-8(2)(y+1)²-6(y+1)=-8
(1)
y的4次方-y²=6
y的4次方-y²-6=0
(y²-3)(y²+2)=0
(y+√3)(y-√3)(y²+2)=0
∴y=√3或y=-√3
(2)第二题应该是:(y+1)²-6(y+1)=-8
(y+1)²-6(y+1)=-8
(y+1)²-6(y+1)+8=0
[(y+1)-4][(y+1)-2]=0
(y-3)(y-1)=0
∴y=3
或y=1

(1)、y的4次方-y²=6,
( 利用十字相乘法分解)
y的4次方-y²=6=0
(y²+2)(y²-3)=0
(y²+2)(y+√3)(y-√3)=0
∴y=√3或y=-√3
(2) (y+...

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(1)、y的4次方-y²=6,
( 利用十字相乘法分解)
y的4次方-y²=6=0
(y²+2)(y²-3)=0
(y²+2)(y+√3)(y-√3)=0
∴y=√3或y=-√3
(2) (y+1)²-6(y+1)=-8
( 利用十字相乘法分解)
(y+1)²-6(y+1)+8=0
[(y+1)-2][(y+1)-4]=0
(y-1)(y-3)=0
∴y=1或者y=3
此为正解,希望能帮到你,请采纳!!!

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(1) y^4-y^2=6
Y^4-y^2-6=0
(Y^2-3)(Y^2+2)=0
(Y+根号3)(Y-根号3)(Y^2+2)=0
(2)(y-1)²-6(y+1)=-8
(Y-1)^2-6Y-6+8=0
(Y-1)^2-6(Y-...

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(1) y^4-y^2=6
Y^4-y^2-6=0
(Y^2-3)(Y^2+2)=0
(Y+根号3)(Y-根号3)(Y^2+2)=0
(2)(y-1)²-6(y+1)=-8
(Y-1)^2-6Y-6+8=0
(Y-1)^2-6(Y-1)-4=0
(Y-1)(Y-1-6)-4=0
第二题感觉题目不对!

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