main( ) { int m=5,n=5; if (++m>=n) printf(“\\m=%d>=n=%d\n”,m,n); else printf(“m=%d\n”,m--); }A）A）m=6>=n=5B）\m=6>=n=5C）\m=5>=n=5 D）m=5

#include int gcd(int m,int n) { if(m%n==0) printf(%d ,n); else gcd(n,m%n); } main() { i#includeint gcd(int m,int n){if(m%n==0) printf(%d ,n);elsegcd(n,m%n);} main(){int m,n;scanf(%d%d,&m,&n);printf(%d,gcd(n,m%n));}求m整除n #define N 20 fun(int a[],int n,int m) {int i; for(i=m;i>n;i--)a[i+1]=a[i]; return m; } void main() #define N 20fun(int a[],int n,int m){int i;for(i=m;i>n;i--)a[i+1]=a[i];return m;}void main(){ int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,0,N/2);for(i=0;i #include stdio.hint fun (int k,int *m){if (k%3) *m=k*k;else *m=k/3;}main(){int (*p) (int,int *),m;p=fun;(*P) (78,&m);printf ( %d ,m);} define M 5#define N M+M main(){int k;k=N*N*5; printf(%d,k);问结果是多少啊?呜呜,我做的不对, #include int gcd(int m,int n) { if(m%n==0) printf(%d ,n); else gcd(n,m%n); } main() { i#includeint gcd(int m,int n){if(m%n==0) printf(%d ,n);elsegcd(n,m%n);} main(){int m,n;scanf(%d%d,&m,&n);printf(%d,gcd(n,m%n));}求m/n整除 程序有错 #include < stdio.h > main() { int m,n; scanf(%d%d,&m,&n); while (m!=n) { while(m>n) m=m-n;while(m main() { int n=4; while(n--) printf(%d,--n); } C语言求平均数问题#include #define N 5 void main(int){int c[N],d[N],f[N];int i,j,m;float s=0.0,h=0.0,k=0.0;for(i=0;i 编写程序 计算组合数的公式#include int main(void){double fact(int n,int m);int i,p,m,n;double result,product,case;printf(Enter n,m:);scanf(%d%d,&n,&m);for(i = 0;i syntax error :identifier 'n'#includeint i,n,s;int proone(int i,n,s=0);int protwo(int i,n,s=0);void main( ){double s1,s2;int m,n;cout #include main() { int m=8,n=5; printf(%d ,m*=m-n); printf(%d ,m=m+1,n-1,m+n); }结果是2425请问25是怎么出来的? 编写一个函数,求一组数中的最大值和最小值源程序：int min;int maximum(n)；main(){ int i,n[10],m;clrscr();for(i=0；i 1.以下程序输出结果是( ) main() { int m=5;if(m++>5) printf(%d,m);else printf(%d ,m--); #include int main() { int a[150];int m,n,i,j,t; while(scanf(%d %d,&m ,&n)!=EOF) {printf(#includeint main(){int a[150];int m,n,i,j,t;while(scanf(%d %d,&m ,&n)!=EOF){printf(%d~%d prime include:,m,n);t=0;for ( i=m+1;i #define N 20 fun(int a[],int n,int m) { int i; for(i=m;i>=n;i--) a[i+1]=a[i]; return a[a+1]; } main#define N 20fun(int a[],int n,int m){ int i;for(i=m;i>=n;i--)a[i+1]=a[i];return a[a+1];}main(){int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,2,9);for(i=0;i #includeint a(int x);int b(int y);int main(){int m,n;n=6;m=a(n);printf(%d ,m);return 0;}int a(int x){x=b(x+3);return x;}int b(int y){return y+1;} #include int ZDGYS(int m,int n) { int r; scanf(%d%d,&m,&n); r=m%n; while(r!=0) { m=n; n=#includeint ZDGYS(int m,int n){int r;scanf(%d%d,&m,&n);r=m%n;while(r!=0){m=n;n=r;r=m%n;}return n;}main(){printf(%d,r);}求m,n的最大公约数 看看哪有 #include int main() { int a[100]; int n,i,j,k,t,m; scanf(%d %d ,&m,&n);#includeint main(){int a[100];int n,i,j,k,t,m;scanf(%d %d ,&m,&n);scanf(%d,&a[i]);for(i=0;i