2^(2+log2 5)—2^(log2 3乘以log3 5)的值为

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2^(2+log25)—2^(log23乘以log35)的值为2^(2+log25)—2^(log23乘以log35)的值为2^(2+log25)—2^(log23乘以log35)的值为2^(2+lo

2^(2+log2 5)—2^(log2 3乘以log3 5)的值为
2^(2+log2 5)—2^(log2 3乘以log3 5)的值为

2^(2+log2 5)—2^(log2 3乘以log3 5)的值为
2^(2+log2 5)—2^(log2 3乘以log3 5)的值为
=2^2*2^(log2 5)-2^(log2 5)
=4*5-5
=15

首先要知道m^(logm n)=n m*loga b=loga (b^m)
2^(2+log2 5)=2^(log2 4 +log2 5)=2^(log2 20)=20
2^(log2 3乘以log3 5)=2^(log2 3)^(log3 5)=5
原式=20-5=15