log2(20)-log2(5)+2log3(2)×log4(3)

log2(20)-log2(5)+2log3(2)×log4(3) log2^(4^7*2^5)+log2^6-log2^3 log2 50-2log2 5 等于多少? log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X 2^log2(20)=? log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) 计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9 log2 3/log2 5等于log2 3-log2 5么? log2 5/4+log2 5 [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 log2 20---log2 5+log3 4 * log4 3 等于什么 log2 5/log2 3为什么等于log3 5 log2 5,log2 3的2是角标 log3 5的3是角标log2 5/log2 3为什么等于log3 5log2 log2 3的2是角标，log3 5的3是角标 4^1/2（log2^9-log2^5）的值 , 解2log2^(x-5)=log2^(x-1)+1 求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？ log2(log2 log2(4^7*2^5)