2^log2(20)=?

2^log2(20)=? log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X (log2 9)/(log2 8) = 2/3(log2 3) 2log2 10—log2 25=? 2log2^3= log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2(x – 2 ) + 2 = log2(5)log2(x – 2 ) + 2 = log2(5) log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1 (log2) ^2 - log5 *log20课本上 等于 （log2）^2 +(1+log2)(1-log2) = 1;（log2）^2 +(1+log2)(1-log2) 是怎么来的? log2 4+log2 (x+2)怎么算?log2 4+log2 (x+2)=log2 (4x+8) log2 (log2 16)=? [log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204 log2(20)-log2(5)+2log3(2)×log4(3) log2(2x)*log2(x)=2 x=? 求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？ 求导 y=log2(x^2)-log2(x) 求解log2(3x)=log2(2x+1) 解方程log2(2-x)=log2(x-1)+1