5X+3Y=3483X+2Y=216

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5X+3Y=3483X+2Y=2165X+3Y=3483X+2Y=2165X+3Y=3483X+2Y=216方法一：加减消元法5X+3Y=348.①3X+2Y=216.②1.先把一个未知数的系数通成同

5X+3Y=3483X+2Y=216
5X+3Y=348
3X+2Y=216

5X+3Y=3483X+2Y=216
方法一：加减消元法
5X+3Y=348 .①
3X+2Y=216 .②
1.先把一个未知数的系数通成同样的数
①*3 :15X+9Y=1044
②*5 :15X+10Y=1080
2.在用加减消元法
②-①：Y=36
3.将Y=36带入到①中：
5X+108=348
解得X=48
所以X=48Y=36为原方程组的解（大括号包起）
方法二：带入消元法
5X+3Y=348 .①
3X+2Y=216 .②
由①得：5X+3Y=348
5X=348-3Y
X=(348-3Y)/5 .③
将③带入②得：3*[(348-3Y)/5]+2Y=216
解得Y=36
将Y=36带入②中,得3X+2*36=216
解得X=48
所以X=48Y=36为原方程组的解（大括号包起）

5X+3Y=348 ----1
3X+2Y=216 ----2
1*2得
10X+6Y=696---3
2*3得
9X+6Y=648---4
3-4得:X=48
把X=8代入2,得:144+2Y=216
Y=36

5X+3Y=348 ...(1)
3X+2Y=216....(2)
2*(1)-3*(2):x=48
5*(2)-3*(1):y=36
x=48
y=36

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