①2x+(x-4)-(5x-4)②3(a^2-2a-3)-5(-5a^2-2)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 02:35:36
①2x+(x-4)-(5x-4)②3(a^2-2a-3)-5(-5a^2-2)①2x+(x-4)-(5x-4)②3(a^2-2a-3)-5(-5a^2-2)①2x+(x-4)-(5x-4)②3(a^2
①2x+(x-4)-(5x-4)②3(a^2-2a-3)-5(-5a^2-2)
①2x+(x-4)-(5x-4)②3(a^2-2a-3)-5(-5a^2-2)
①2x+(x-4)-(5x-4)②3(a^2-2a-3)-5(-5a^2-2)
①=2x+x-4-5x+4=-2x
②:3a²-6a-9+25a²+10=28a²-6a+1
①2x+(x-4)-(5x-4)=2x+x-4-5x+4=-2x
②3(a^2-2a-3)-5(-5a^2-2)=3a²-6a-9+25a²+10=28a²-6a+1
①2x+(x-4)-(5x-4)
=2x+x-4-5x+4
=-2x
②3(a^2-2a-3)-5(-5a^2-2)
=3a^2-6a-9+25a^2+10
=28a^2-6a+1
①3a(5a-2b) ②(x-3y) ×(-6x) ③化简x(x-1)+2x(x+1)-3x(2x-5) ①(x+2)(x+3)②(X-4)(x+1)
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
a+x/x+1 ,x/x^2-2x-3 ,a/x^2+4x+3
计算题:① <(x-1/x+1)-(x+1/x-1)>÷x+3/x*x+4x+4)② (a*a-2ab+b*b)/(a*a+ab)*(a+b)/(ab-b*b)③ (2x/x*x-1)-1/(x-1)④ -a-6约分:① 1/2*x*x*y ,1/3*x*y*y② 1/(2x+2) ,3/(x*x-1)化简:① (3+x)/(2+x)+(x*x-4)
一.填空题:分解因式:①2(x+x)-3(x-x)-2= ②4x-5x-6= 若x-1是x+x+a的一个因式,则a=
一道数学题,x(2x-5)>2x²-3x-4 ①(x+1)(x+3)+8x>(x+5)(x-5)-2 ②
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
(x+3x+5x...+2009x)-(2x+4x+6x+...+2010x)
matlab中a(x)=x^4+3x^3+9x-18 b(x)=x^5-4x^3-18x+7 c(x)=x^7+6x^5+9x^3-5x^2-2 d(x)=x^9-8x^7+6x^5-4x^4+d(x)=x^9-8x^7+6x^5-4x^4+6x^2+3 求e(x)=a(x)*b(x)*c(x)*d(x)
( A/X-5 ) + ( B/X+2 ) = 5X-4/X^2-3X-10 ^-^
x^5-x^4+x^3-x^2+x-1
求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X
EXCEL两表间同时满足两个条件数据引用如题:表1为原始数据表1 2 3 4 5 6 7 8 9 10.A X X X X X X X X X XB X X X X X X X X X XC X X X X X X X X X XD X X X X X X X X X X .表2(A列) (B列) (C列)A 1A 3B 8B 5C 2D 3......
因式分解(^代表几次方,) ①x^3+6x+1+6 ②2x^4-x^3-6x^2-x+2 ③(x-y)^2-3(x-y)-10 ④4a^2-b^2+4a-2b⑤x^2-2xy+y^2-2x+2y-3 ⑥x^5+x+1⑦(x+y-2xy)(x+y-2)+(xy-1)^2⑧x^2-y^2-2x-4y-3⑨7x^2-19x-6⑩x^3+(2a+1)x^2+(a^2+2a-1)x+a^2-1x是 唉可思
1.已知a^2+a+1/4=0.求(a^3-1)/(a^5+a^4-a^3-a^2) 2.如果关于x的方程(x+a)(x+b)+(x+b)(x+c)+(x+c)(x+a)=0有两个等根,求证a=b=c 3.解方程组①根号x+根号(x+7)+2根号(x^2-7x)=35-2x②x+y+xy=19,x^2+y^2=25
若 (2x-1)^5 =a⑤x^5 +a④x^4 +a③x^3 +a②x^2 +a①x+a零求a②+a④的值
分式计算:①(1/x-4)-(2/x-3)=(3/x-2)-(4/x-1) ②(x+3/x+4)+(x+8/x+9)=(x+4/x+5)+(x+7/x+8)
难倒爱因斯坦的九宫格X 7 X | X 8 1 | X X X |X X X | X 4 X | 7 5 9 |X X 5 | 7 X 9 | X 1 4 |5 X X | X X 8 | 3 9 X |3 9 6 | 4 X 7 | X X 2 |X 8 7 | 9 X X | X X X |4 X X | 6 X 5 | X X X | X X 4 | X X 1 |2 X X | X X X | X X X | X 3 X | X X X |X 6