已知x2+y2=20,x2+xy-2y2=2(x+2y),求x+y的值
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已知x2+y2=20,x2+xy-2y2=2(x+2y),求x+y的值已知x2+y2=20,x2+xy-2y2=2(x+2y),求x+y的值已知x2+y2=20,x2+xy-2y2=2(x+2y),求
已知x2+y2=20,x2+xy-2y2=2(x+2y),求x+y的值
已知x2+y2=20,x2+xy-2y2=2(x+2y),求x+y的值
已知x2+y2=20,x2+xy-2y2=2(x+2y),求x+y的值
因为x2+xy-2y2=2(x+2y)即(x-y)(x+2y)=2(x+2y)所以x-y=2(x-y)2=x2-2xy+y2=4所以xy=(x2+y2-4)/2=(20-4)/2=8(x+y)2=x2+y2+2xy=20+2×8=36所以x+y=6
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