tga+ctga=6则sin2a=
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tga+ctga=6则sin2a=tga+ctga=6则sin2a=tga+ctga=6则sin2a=tga+ctga=6tga+1/tga=6((tga)^2+1)/tga=6(tga)^2+1=6
tga+ctga=6则sin2a=
tga+ctga=6则sin2a=
tga+ctga=6则sin2a=
tga+ctga=6
tga+1/tga=6
((tga)^2+1)/tga=6
(tga)^2+1=6tga
sin2a
=2tga/(1+tg^2 a)
=2tga/6tga
=1/3
tga+ctga
=sina/cosa+cosa/sina
=1/(sinacosa)
=2/sin2a=6
所以sin2a=1/3
tga+ctga=6
而tga+ctga=sina/cosa+cosa/sina=[(sina)^2+(cosa)^2]/(sinacosa)
=1/(sinacosa)
依题意:1/(sinacosa)=6
故sinacosa=1/6
sin2a=2*sinacosa=2*1/6=1/3
tga+ctga=6则sin2a=
tga·ctga=?
A为锐角,tga乘以ctga=( )
sin2a=2tga/(1+(tga)^2)
化简:(1+cos2A)/(ctgA/2-tgA/2)=?
求证题能不能写详细点要步骤.急!(cos^2a-sin^2a)/sinacosa=2ctg2a、ctga-tga=2ctg2a、(1+sin2a-cos2a)/(1+sin2a+cos2a)=tga、2sin^2(a/2)+cosa=1
tga/2=1/2,则sin2a=?RT
已知sina+cosa=2/3,求(1+cos2a)/(ctga/2-tga/2)的值.
tga=1/2,sin2a sin^2a=?
化简:1/(tg3a-tga)-1/(ctg3a-ctga)
tg(A+B)=3tgA,求证2sin2B-sin2A=sin(2A+2B)
tg(A+B)=3tgA,2sin2B-sin2A=sin(2A+2B)
已知[2(sin^2)a+sin2a]/(1+tga)=k (∏/4
三角函数值的计算1 tga=0.8375 2 tga=0.4188 3 tga=0.2094 4 tga=0.1047 5 tga=1.650 6 tga=0.8250 7 tga=0.4125 8 tga=2.675 9 tga=1.338 10 tga=0.6688 帮我求一下a的角度啊 我不懂啊
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tgA=6,求A=?求角度值tgA=6,问A=多少?
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