1/(log1/4 1/9) +1/(log1/5 1/3)等于
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1/(log1/41/9)+1/(log1/51/3)等于1/(log1/41/9)+1/(log1/51/3)等于1/(log1/41/9)+1/(log1/51/3)等于公式:loga^nb^m=
1/(log1/4 1/9) +1/(log1/5 1/3)等于
1/(log1/4 1/9) +1/(log1/5 1/3)等于
1/(log1/4 1/9) +1/(log1/5 1/3)等于
公式:loga^n b^m =m/nloga b loga b*logb a=1
原式=1/log2 3+1/log5 3
=log3 2+log3 5
=log3 10
1/log1/41/9+1/log1/51/3= 急
1/(log1/4 1/9) +1/(log1/5 1/3)等于
log1/4(x+3)-log4(x-1)=log1/4(x+9)?
2^(log1/4为底1)=?
log1/2(9^(x-1)-5)=log1/2(3(x-1)-2)-2
log1/2(x+1)>log1/4(3x+4)怎么解最好写过程
解不等式:log1/x(x+1)>log1/x(3x+4)
解不等式 log1/2底(2x+1)>log1/2底(4-x)
log1/2(√x +1) - log1/2(√x -1)
求证:log1/2(1/4^a+1/4^b)
3/8*log3/8+1/4*log1/4 怎么算
解不等式:log1/3(x^2-4x+3)>-1
log1/2(4^x+2^(x+1))>0
log1/4 2-log1/8 2这个该怎么算log1/4 2-log1/8 2这两个数底数不同真数相同 1/4是1/8的二倍 这个该怎么算
Log1/2(x^2-x-2)>Log1/2(2x-1)-1怎么解?我的解法是:Log1/2(x^2-x-2)>Log1/2(4x-2)x^2-x-21/2综上所述,2
1+log1/2^(4-a^x)=log1/4^(a^x-1)底数不同怎么换啊?
a=|log1/3(1/4 )|、 b=|log1/2(3/2)| 比较a、b的大小.
log1/41/9,其中1/4是底数,1/9是真数,求对数,