(sin22°+cos45°sin23°)/(cos22°-sin45°sin23°)=
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(sin22°+cos45°sin23°)/(cos22°-sin45°sin23°)=(sin22°+cos45°sin23°)/(cos22°-sin45°sin23°)=(sin22°+cos4
(sin22°+cos45°sin23°)/(cos22°-sin45°sin23°)=
(sin22°+cos45°sin23°)/(cos22°-sin45°sin23°)=
(sin22°+cos45°sin23°)/(cos22°-sin45°sin23°)=
把sin22展开成sin45cos23-cos45sin23,cos22展开成cos45cos23+sin45sin23,即可得到原式=tan45=1
(sin22°+cos45°sin23°)/(cos22°-sin45°sin23°)=
cos23°cos22°-sin23°sin22°=
cos22°cos23°-sin22°sin23°等于
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