已知1-1/2+1/3-1/4+1/5-...-1/1318+1/1319=a/b,a与b互质,证明a能被1979整除
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/15 20:49:28
已知1-1/2+1/3-1/4+1/5-...-1/1318+1/1319=a/b,a与b互质,证明a能被1979整除已知1-1/2+1/3-1/4+1/5-...-1/1318+1/1319=a/b
已知1-1/2+1/3-1/4+1/5-...-1/1318+1/1319=a/b,a与b互质,证明a能被1979整除
已知1-1/2+1/3-1/4+1/5-...-1/1318+1/1319=a/b,a与b互质,证明a能被1979整除
已知1-1/2+1/3-1/4+1/5-...-1/1318+1/1319=a/b,a与b互质,证明a能被1979整除
S=1-1/2+1/3-1/4+1/5-...-1/1318+1/1319
=(1+1/2+1/3+1/4+...+1/1319)-2*(1/2+1/4+...+1/1318)
=(1+1/2+1/3+1/4+...+1/1319)-(1+1/2+...+1/659)
=1/660+1/661+...+1/1319
1/660+1/1319=1979/(660*1319),
1/661+1/1318=1979/(661*1318),
.
1/989+1/990=1979/(989*990).
相加,并记B=660*661*...*1318*1319,得
S=1979/(660*1319)+1979/(661*1318)+...+1979/(989*990)
=1979A/B,
1979是质数,大于B中所有质因数,1979A/B约简时1979不可能被约去,所以若S约简成a/b,a一定能被1979整除.
可以