设函数f(x)=ax^3-3x+1(x属于R),若对于任意的x属于(0,1】都有f(x)大于等于0成立,则实数a的取值范围为

设函数f(x)=x^3+ax^2-9x-1(a 设函数f(x)=x^3+ax^2-9x-1(a 设函数f(x)=x^3+ax^2-9x-1(a 设函数f(x)=x^3+ax^2-9x-1(a 急设函数f(x)=2{x}^{3}+ax-2,已知f(x) 设函数f(x)=-1/3x设函数f(x)=-1/3x 设函数f(x)=-1/3x^3+2ax^2+1/3a(0 设函数f(x)=ax^2-2x+3,对于满足1 （x-3)(2x-1)设函数f(x)=ax^³+b,已知f(1)=0,则 设函数f(x)=ax 已知函数f(x)=x^3+ax^2+x+1,设函数f(x)在区间(-2/3,-1/3)内是减函数,求a的范围? 设函数f(x)=ax+3,若f'(1)=3,则a= 设函数f(x+1)=ax+1,且f(2)=3,则a= 设函数f(x)=ax+2,不等式｜f(x)｜ 设函数f(x)=ax^2+bx+c((a≠0),满足f(x+1)=f(-x-3),且f(-2)>f(2),解不等式f(-2x^2+2x-3)>f(x^2+4x+3) 设函数f(x)= -1/3x^3+2ax^2-3a^2x+a/3(0 设函数f(x)=-1/3x~3+2ax~2-3a~2x+1(0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+1(0