【(2x+y)(2x-y)+(x+y)的平方-2(2x的平方-xy)】,其中2y+2分之x=10
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【(2x+y)(2x-y)+(x+y)的平方-2(2x的平方-xy)】,其中2y+2分之x=10【(2x+y)(2x-y)+(x+y)的平方-2(2x的平方-xy)】,其中2y+2分之x=10【(2x
【(2x+y)(2x-y)+(x+y)的平方-2(2x的平方-xy)】,其中2y+2分之x=10
【(2x+y)(2x-y)+(x+y)的平方-2(2x的平方-xy)】,其中2y+2分之x=10
【(2x+y)(2x-y)+(x+y)的平方-2(2x的平方-xy)】,其中2y+2分之x=10
解
2y+x/2=10——这个吗?
两边乘以2得:
4y+x=20
[(2x+y)(2x-y)+(x+y)²-2(2x²-xy)]
=[(4x²-y²)+(x²+2xy+y²)-(4x²-2xy)]
=(4x²+x²-4x²)+(-y²+y²)+(2xy+2xy)
=x²+4xy
=x(x+4y)
=20x
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
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