1/[(1/(x+18)+1/(x+32)]=x,求X,
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1/[(1/(x+18)+1/(x+32)]=x,求X,1/[(1/(x+18)+1/(x+32)]=x,求X,1/[(1/(x+18)+1/(x+32)]=x,求X,先把中括号里的乘过去1=x/(x
1/[(1/(x+18)+1/(x+32)]=x,求X,
1/[(1/(x+18)+1/(x+32)]=x,求X,
1/[(1/(x+18)+1/(x+32)]=x,求X,
先把中括号里的乘过去
1=x/(x+18)+x/(x+32)
然后乘分母,别嫌麻烦
(x+18)(x+32)=x(x+32)+x(x+18)
x2+50x+576=2x2+50x
x2=576
x=24
很简单的,只要你用心算
x/x+(1-x)/x-1/x
因式分解(x+1)(x+2)-x-10(x²-x)²-18(x²-x)+72
(x^2-x)^2-18(x^2-x)+72(x+1)(x+2)-x-10
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(x+1)(x-1)(x-x+1)(x+x+1)
分解因式----(X*X-X)(X*X-X-2)+1
X(X-1)=X
1.1/x|x/(x+1)|
x/x-1[1+(x-1/x)]
x(x-1)=18
x-1/x÷(x-1/x)
】x(x+1)+x^2(x-1)
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
计算1/[x(x+3)]+1/[(x+3)(x+6)]+.+1/[(x+15)(x+18)]=?
1/x(x+3)+1/(x+3)(x+6)+...+1/(x+15)(x+18)