(x+1)(x-1)(x-x+1)(x+x+1)
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(x+1)(x-1)(x-x+1)(x+x+1)(x+1)(x-1)(x-x+1)(x+x+1)(x+1)(x-1)(x-x+1)(x+x+1)(x+1)(x-1)(x-x+1)(x+x+1)=(x^
(x+1)(x-1)(x-x+1)(x+x+1)
(x+1)(x-1)(x-x+1)(x+x+1)
(x+1)(x-1)(x-x+1)(x+x+1)
(x+1)(x-1)(x-x+1)(x+x+1)
=(x^2-1)(x+1-x)(x+1+x)
=(x^2-1)[(x+1)^2-x^2]
=x^2(x+1)^2-x^4-(x+1)^2+x^2
=x^2(x^2+2x+1)-x^4-x^2-2x-1+x^2
=x^4+2x^3+x^2-x^4-x^2-2x-1+x^2
=2x^3+x^2-2x-1.
或者：
(x+1)(x-1)(x-x+1)(x+x+1)
=(x+1)(x-1)(x+x+1)
=(x+1)(x-1)(2x+1)
=(x^2-1)(2x+1)
=2x^3+x^2-2x-1
平方差公式
公式
(x+1)(x-1）=x^2-1
(x-x+1)(x+x+1) =2x+1
结果得想2x^3-x^2-2x-1
答案：x^6-1
过程： 先运用立方和与差公式，然后运用平方差公式
原式=[(x+1)(x-x+1)][( x-1)(x+x+1)]= (x^3+1)(x^3-1)=x^6-1
x/x+(1-x)/x-1/x
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(x+1)(x-1)(x-x+1)(x+x+1)
分解因式----（X*X-X)(X*X-X-2)+1
X(X-1)=X
1.1/x|x/(x+1)|
x/x-1[1+(x-1/x)]
x-1/x÷(x-1/x)
】x(x+1)+x^2(x-1)
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
x>1/1-x
x+1/x-1
(X + 1) /(x - 1)
(1+X)/(1-X)
|x+1|+|x-1|
/X-3/-/X-1/