解下列方程组1.(x-y+2)(x+y)=0 x²+y²=8 2.(x+y)(x+y-1)=0 (x-y)(x-y-1)=0

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/23 12:02:47
解下列方程组1.(x-y+2)(x+y)=0x²+y²=82.(x+y)(x+y-1)=0(x-y)(x-y-1)=0解下列方程组1.(x-y+2)(x+y)=0x²+y

解下列方程组1.(x-y+2)(x+y)=0 x²+y²=8 2.(x+y)(x+y-1)=0 (x-y)(x-y-1)=0
解下列方程组1.(x-y+2)(x+y)=0 x²+y²=8 2.(x+y)(x+y-1)=0 (x-y)(x-y-1)=0

解下列方程组1.(x-y+2)(x+y)=0 x²+y²=8 2.(x+y)(x+y-1)=0 (x-y)(x-y-1)=0
1.如果是初中数学可以有偷懒的方法,就是两数相乘=0
必然至少其中之一为0
1、如果x+y=0
则x=-y,带入x²+y²=8
得到x=2,y=-2 或者x=-2,y=2
2、如果x-y+2=0
则x=y-2带入x²+y²=8
得x=√3-1,y=√3+1 或x=-√3-1 ,y=-√3+1