(x+2y)²-(x-2y)(x+y)
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(x+2y)²-(x-2y)(x+y)(x+2y)²-(x-2y)(x+y)(x+2y)²-(x-2y)(x+y)(x+2y)²-(x-2y)(x+y)=x&#
(x+2y)²-(x-2y)(x+y)
(x+2y)²-(x-2y)(x+y)
(x+2y)²-(x-2y)(x+y)
(x+2y)²-(x-2y)(x+y)
=x²＋4xy＋4y²－﹙x²＋xy－2xy－2y²﹚
=x²＋4xy＋4y²－x²＋xy＋2y²
=5xy＋6y²