若x^2+9y^2-2x+12y+5=0,求x+y^2
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若x^2+9y^2-2x+12y+5=0,求x+y^2若x^2+9y^2-2x+12y+5=0,求x+y^2若x^2+9y^2-2x+12y+5=0,求x+y^2x^2+9y^2-2x+12y+5=0
若x^2+9y^2-2x+12y+5=0,求x+y^2
若x^2+9y^2-2x+12y+5=0,求x+y^2
若x^2+9y^2-2x+12y+5=0,求x+y^2
x^2+9y^2-2x+12y+5=0
(x^2-2x+1)+(9y^2+12y+4)=0
(x-1)^2+(3y+2)^2=0
因为(x-1)^2>=0 (3y+2)^2>=0
所以(x-1)^2=0 (3y+2)^2=0
x-1=0 3y+2=0
x=1 y=-2/3
x+y^2=1+(-2/3)^2=1+4/9=13/9
x²+9y²-2x+12y+5
=x²-2x+1+9y²+12y+4
=（x-1）²+（3y+2）²
=0
∴x=1，y=-2/3
∴x+y²=1+ 4/9=13/9
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