(x-1)-(x-1)∧2+(x-1)∧4+(x-1)∧5的展开式中x∧3的系数是急
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(x-1)-(x-1)∧2+(x-1)∧4+(x-1)∧5的展开式中x∧3的系数是急(x-1)-(x-1)∧2+(x-1)∧4+(x-1)∧5的展开式中x∧3的系数是急(x-1)-(x-1)∧2+(x
(x-1)-(x-1)∧2+(x-1)∧4+(x-1)∧5的展开式中x∧3的系数是急
(x-1)-(x-1)∧2+(x-1)∧4+(x-1)∧5的展开式中x∧3的系数是
急
(x-1)-(x-1)∧2+(x-1)∧4+(x-1)∧5的展开式中x∧3的系数是急
解x^3的项为C(4,1)x^3(-1)^1+C(5,2)x^3(-1)^2
=-4x^3+10x^3
=6x^3
故x∧3的系数是6
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