若实数x、y满足x^2+4x+y^2-6y+12=0,则x=()y=()?是13,打错了
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若实数x、y满足x^2+4x+y^2-6y+12=0,则x=()y=()?是13,打错了若实数x、y满足x^2+4x+y^2-6y+12=0,则x=()y=()?是13,打错了若实数x、y满足x^2+
若实数x、y满足x^2+4x+y^2-6y+12=0,则x=()y=()?是13,打错了
若实数x、y满足x^2+4x+y^2-6y+12=0,则x=()y=()?
是13,打错了
若实数x、y满足x^2+4x+y^2-6y+12=0,则x=()y=()?是13,打错了
修改一下题目:x^2+4x+y^2-6y+13=0 x^2+4x+4+y^2-6y+9=0 (x+2)^2+(y-3)^2=0 所以 x+2=0,x=-2; y-3=0,y=3.
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