设f(x)=lnx+x^1/2-1,证明:当x>1时f(x)<3/2(x-1)

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设f(x)=lnx+x^1/2-1,证明:当x>1时f(x)<3/2(x-1)设f(x)=lnx+x^1/2-1,证明:当x>1时f(x)<3/2(x-1)设f(x)=lnx+x^1/2-1,证明:当

设f(x)=lnx+x^1/2-1,证明:当x>1时f(x)<3/2(x-1)
设f(x)=lnx+x^1/2-1,证明:当x>1时f(x)<3/2(x-1)

设f(x)=lnx+x^1/2-1,证明:当x>1时f(x)<3/2(x-1)
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