x + (11-3)y =17 x + (23-3)y =35 2远一次,、、、
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 16:51:54
x+(11-3)y=17x+(23-3)y=352远一次,、、、x+(11-3)y=17x+(23-3)y=352远一次,、、、x+(11-3)y=17x+(23-3)y=352远一次,、、、x+(1
x + (11-3)y =17 x + (23-3)y =35 2远一次,、、、
x + (11-3)y =17 x + (23-3)y =35 2远一次,
、、、
x + (11-3)y =17 x + (23-3)y =35 2远一次,、、、
x + (11-3)y =17
x + (23-3)y =35
相减
20y-8y=35-17
12y=18
所以
y=3/2
x=17-8y=5
x+(11-3)*y=17 x+(23-3)*y=35 求x,y
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
6(x+y)的平方-11(x+y)(x-y)+3(x-y)的平方=?
分式 (11 18:8:17)已知x/y=2,求x·x-x·y+3y·y/x·x+x·y+6y·y的值
推倒公式:(x+y)(x*x-3x+y*y)=x*x*x+y*y*y怎么做.
(x+y-5)*(x+y-5)+(x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
根据3(x+y)-2(x-y)=11,4(x+y)+3(x-y)=9可得出x+y= ,x-y=
(x+y)(x+2y)(x+3y)(x+4y)=-40y的值为根号11
请解答方程组:(39)2x+y=5 (40)x+y=7 (41)2x+3y=12 (42)2x+y=3ax+3y=7 2x-y=8 3x+4y=17 3x-5y=11(43)3x+y=82 (44)3(x-1)=y+5 45 x/4+y/3=7 (46)x+y/3 +x-y/2=610x-11y=87 5(y-1)=3(x+5) 2/3x+y/2=14 3(x+y-)2(x-y)=28
用代入消元法解方程组: {y=x+1, 3x+4y=11 {x-5y=0, 3x+2y=17 {5x-3y=-1, 3x+y=5 {2x-y+5, 3x+4y=2{x+1分之三 =2y ,2(x+1)-y=11{x+y=9, 3(x+y)+2x=33
用代入消元法解方程组:{y=x+1,3x+4y=11 {x-5y=0,3x+2y=17 {5x-3y=-1,3x+y=5 {2x-y+5,3x+4y=2{x+1分之三 =2y ,2(x+1)-y=11{x+y=9,3(x+y)+2x=33
3x+2y=5x+2,2(3x+2y)=11x+17
x+y=5; x^y+y^x=17
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²=