化简[(cos^2a-sin^2B)/(sin^2a*cos^2B)]-cot^2a*cot^2B
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化简[(cos^2a-sin^2B)/(sin^2a*cos^2B)]-cot^2a*cot^2B化简[(cos^2a-sin^2B)/(sin^2a*cos^2B)]-cot^2a*cot^2B化简
化简[(cos^2a-sin^2B)/(sin^2a*cos^2B)]-cot^2a*cot^2B
化简[(cos^2a-sin^2B)/(sin^2a*cos^2B)]-cot^2a*cot^2B
化简[(cos^2a-sin^2B)/(sin^2a*cos^2B)]-cot^2a*cot^2B
[(cos^2a-sin^2B)/(sin^2a*cos^2B)]-cot^2a*cot^2B
代入以下的公式应该可以了吧!
cos2a=(cosa)^2-(sina)^2=2(cosa)^2 -1=1-2(sina)^2
cos2a=(cosa)^2-(sina)^2
sin2a=2sina*cosa
tan2a=2tana/[1-(tana)^2]
化简cos(a+b)cos(a-b)+sin^2b
化简sin^2a+sin^2b-sin^2a*sin^2b+cos^2a*cos^2b
sin^2a+sin^2b-sin^2a * sin^2b+cos^2a * cos^2b 化简
化简(sin(a-b)-2sin a cos b)/2sin a sin b +coa(a+b)
化简sin^2acos^b-cos^2asin^2b+cos^a-cos^2b
化简[sin(2A+B)]/sinA-2cos(A+B)
化简[(cos^2a-sin^2B)/(sin^2a*cos^2B)]-cot^2a*cot^2B
化简cos(a+b)cos(a-b)+sin^2b
sin^2 (A)+sin^2(B)-sin^2(A)sin^2(B)+cos^2(A)cos^2(B)
证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1
cos^2a-cos^2b=m,那么sin(a+b)sin(a-b)=?
证明sin(A+B)sin(A-B)=cos^2B-cos^2A
化简:sin^2a+sin^2b+2sina*sinb*cos(a+b)
sin∧2a+sin∧2b+2sina*sinb*cos(a+b).化简,
求证cos(a+b)cos(a-b)=cos^2b-sin^2a
求证cos(a+b)cos(a-b)=cos^2a-sin^2b
化简sin^2(a)*sin^2(b)+cos^2(a)*cos^2(b)-1/2cos2a*cos2b
sin(a-b)*cos a-cos(a-b)*sin a=1/5,则cos 2b的值是