求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)
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求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)n是趋于无穷大
求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)
求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)
求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)
n 是趋于无穷大么?就按这个解答.
分子分母同除以 n^4 ,化为 [1/n*(1+1/n)(1+2/n)(1+3/n)] / (1+1/n^2+1/n^4) ,
由于 n 趋于无穷大,所以 1/n、2/n、3/n、1/n^2、1/n^4 极限都等于 0 ,
所以所求极限 =(0*1*1*1)/(1+0+0)= 0 .
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