3/(1^22^2)+5/(2^23^2)+``````+(2n+1)/(n^2*(n+1)^2)的极限怎么求

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3/(1^2*2^2)+5/(2^2*3^2)+``````+(2n+1)/(n^2*(n+1)^2)的极限怎么求3/(1^2*2^2)+5/(2^2*3^2)+``````+(2n+1)/(n^2*

3/(1^2*2^2)+5/(2^2*3^2)+``````+(2n+1)/(n^2*(n+1)^2)的极限怎么求
3/(1^2*2^2)+5/(2^2*3^2)+``````+(2n+1)/(n^2*(n+1)^2)的极限怎么求

3/(1^2*2^2)+5/(2^2*3^2)+``````+(2n+1)/(n^2*(n+1)^2)的极限怎么求
(2n+1) / [ n²(n+1)² ] = 1/n² - 1/(n+1)²
∴原式 = 1 - 1/(n+1)²
极限为 1
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1+5+5+5+5+3+2+2+2+2+2+2+1+2+5 [-2*1/4+(-1/2)3]*(-2*2/3)+(-1*2/3)2÷5/3 1、2、3、5, 1-3/5+1/2-2/5 计算1^2-2^2+3^2-4^2+5^2-6^2+...+(2n-1)^2-(2n)^2 (-2/3)+1/2+4/5+(-1/2)+(-1/3) 2+ 2^3 +2^5 +...+(2^2n-3) +(2^2n-1)=? 3/(1^2)+5/(1^2+2^2)+7/(1^2+2^2+3^2)+.+(2n+1)/(1^2+2^2+.n^2)=? 2/1*2*3+2/2*3*4+2/3*4*5+...+2/18*19*20 2/1*2*3+2/2*3*4+2/3*4*5+...+2/28*29*30 1 2 3 4 5 1 2 1+1+2+2+3+4+5 1^2+3^2+5^2+.+N^2=多少求四阶行列式1^2 2^2 3^2 4^2 2^2 3^2 4^2 5^2 3^2求四阶行列式1^2 2^2 3^2 4^2 2^2 3^2 4^2 5^2 3^2 4^2 5^2 6^2 4^2 5^2 6^2 7^2 的值 2 1 -2 -3 化简:(2x+1)^2+5(x-1)^2-(3x+2)(3x-2)+2 1/2+3/2^2+5/2^3+...+(2n-1)/2^n= 1/2+3/2^2+5/2^3+...+(2n-1)/2^n=请有才者做做,