(10-√2X×2X-25)÷2=X 解出X 也就是10减根号4X方减25再除以2等于X

解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1 解方程：（2x+5)(4x*x-10x+25)=8x(x*x+1) (10-√2X×2X-25)÷2=X 解出X 也就是10减根号4X方减25再除以2等于X (x²-x+1)÷(x²-x-1)=(x²+x)÷(x²+x-2)解方程 解方程:x-2x+3x-4x+...+99x-100x=25 解方程：x-2x+3x-4x+.+99x-100x=25 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550必须用解方程 xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) x-2x+3x-4x+5x.+99x-100x=25求解 (x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2 x^2-1/x^2+x÷(x-2x-1/x),其中x=√2+1, f(x)=x^2+x (x X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4) f[x -x/8-x*x]=√2 10求x^2 20x^10 x 解方程(x^2-10x+15)/(x^2-6x+15)=3x/(x^2-8x+15) 1/x(x+1)+1/(x+1)(x+2)+...+1/(x+9)(x+10)=1/(x+10),解方程