已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?(注:n不是乘n)
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已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?(注:n不是乘n)已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?(注:n不是乘n)
已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?(注:n不是乘n)
已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?(注:n不是乘n)
已知数列{an}满足a1=2,a(n+1)-an=a(n+1)*an,则a31=?(注:n不是乘n)
两边同除a(n+1)an,得1/an-1/a(n+1)=1
所以数列{1/an}为首项1/a1=1/2,公差-1的等差数列
1/an=1/2-(n-1)=-n+3/2
1/a31=-59/2
a31=-2/59
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