已知x/3=y/4=z/5,求(3x+2y-5z)的值(3x+2y-5z)/x+y+z
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已知x/3=y/4=z/5,求(3x+2y-5z)的值(3x+2y-5z)/x+y+z已知x/3=y/4=z/5,求(3x+2y-5z)的值(3x+2y-5z)/x+y+z已知x/3=y/4=z/5,
已知x/3=y/4=z/5,求(3x+2y-5z)的值(3x+2y-5z)/x+y+z
已知x/3=y/4=z/5,求(3x+2y-5z)的值
(3x+2y-5z)/x+y+z
已知x/3=y/4=z/5,求(3x+2y-5z)的值(3x+2y-5z)/x+y+z
可以设x=3a y=4a z=5a
那么3x+2y-5z=9a+8a-25a=-6a=-2x
x+y+z=3a+4a+5a=12a
所以
(3x+2y-5z)/x+y+z=-6a/12a=-1/2
令X/3=Y/4=Z/5=W,则:X=3W,Y=4W,Z=5W
3x+2y-5z=9W+8W-25W=-6W
好象还少一算式
令x/3=y/4=z/5=u
x=3u y=4u z=5u
3x+2y-5z=8u=8/3x=2y=8/5z
x=0,y=0,z=0.
所以,(3x+2y-5z)=0
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