x+2y-z=12,且x/2=y/3+z/2=k 求k值
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x+2y-z=12,且x/2=y/3+z/2=k求k值x+2y-z=12,且x/2=y/3+z/2=k求k值x+2y-z=12,且x/2=y/3+z/2=k求k值由②式得:x=z=2k,y=3k,再代
x+2y-z=12,且x/2=y/3+z/2=k 求k值
x+2y-z=12,且x/2=y/3+z/2=k 求k值
x+2y-z=12,且x/2=y/3+z/2=k 求k值
由②式得:x=z=2k,y=3k,
再代入①得:2k+2*3k-2k=12即6k=12
解得k=2
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