解x+1/(x-1)-4/(x^2-1)=1

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解x+1/(x-1)-4/(x^2-1)=1解x+1/(x-1)-4/(x^2-1)=1解x+1/(x-1)-4/(x^2-1)=1去分母,得(x+1)^2-4=x^2-1x=1经检验x=1是增根,原

解x+1/(x-1)-4/(x^2-1)=1
解x+1/(x-1)-4/(x^2-1)=1

解x+1/(x-1)-4/(x^2-1)=1
去分母,得(x+1)^2-4=x^2-1
x=1
经检验x=1是增根,原方程无解.

(x+1)/(x-1)-4/(x^2-1)=1
1-2/(x-1)-[2/(x-1)-2/(x+1)]=1
-4/(x-1)=-2/(x+1)
2x-2=4x+4
2x=-6
x=-3

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