解x+1/(x-1)-4/(x^2-1)=1

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/25 04:20:48
解x+1/(x-1)-4/(x^2-1)=1解x+1/(x-1)-4/(x^2-1)=1解x+1/(x-1)-4/(x^2-1)=1去分母,得(x+1)^2-4=x^2-1x=1经检验x=1是增根,原

解x+1/(x-1)-4/(x^2-1)=1
解x+1/(x-1)-4/(x^2-1)=1

解x+1/(x-1)-4/(x^2-1)=1
去分母,得(x+1)^2-4=x^2-1
x=1
经检验x=1是增根,原方程无解.

(x+1)/(x-1)-4/(x^2-1)=1
1-2/(x-1)-[2/(x-1)-2/(x+1)]=1
-4/(x-1)=-2/(x+1)
2x-2=4x+4
2x=-6
x=-3

*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做 解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1 x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 解不等式 (x+1)(x+2)(x+3)(x+4) 解方程(x+1/x-1)+(x-2/x+2)+(x-3/x+3)+(x+4/x-4)=4 x^5-x^4+x^3-x^2+x-1 x^6-x^5+x^4-x^2+x-1 请大神帮我解这个数独 题,我解了很久 了 ,最后 X X X X 3 X 1 5 XX X X X 7 8 6 X 92 9 X X X X X X 7X X X X 6 X 2 X 3X 1 3 7 2 9 4 8 X4 X 2 X 8 X X X X3 X X X X X X 6 48 X 6 3 9 X X X X X 7 1 X 4 X X X X 解分式不等式(x+2)/(x+1)+(x+3)/(x+2)≥(x+1)/x+(x+4)/(x+3) 求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X 解方程:(x+3)/(x+2)-(x+4)/(x+3)=(x+5)/(x+4)-(x+2)/(x+1) 解方程 x+2/x+1+x+8/x+7=x+6/x+5+x+4/x+3 解方程:2x+4x+6x...+100x=1-(x+3x+5x+...+99x) 解方程 (x+2)/(x+1) - (x+4)/(x+3)=(x+6)/(x+5)-(x+8)/(x+7) 解方程:2x(x-2)-6x(x-1)=4x(1-x)+16