已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求A2,A3,A4,A5,A6N为正整数
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已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求A2,A3,A4,A5,A6N为正整数已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求A2,
已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求A2,A3,A4,A5,A6N为正整数
已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求A2,A3,A4,A5,A6
N为正整数
已知数列{an}满足A1=0,A(N+1)=AN减去根号三/根号三AN加1.求A2,A3,A4,A5,A6N为正整数
A(n+1)=An-√3/(√3+1)
=An-√3(√3-1)/2
=An-3/2+√3/2
A2=3/2-√3/2
A3=A2-(-3/2+√3/2)=3-√3
A4=A3-(-3/2+√3/2)=9/2-3√3/2
A5=6-2√3
A6=15/2-5√3/2
首先二次根号的表示为sqrt 再次你能不能加几个括号啊?
这样没法理解!!!!!!!!!
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