计算：(x-y-z)^2-(x-y+z)^2

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计算：(x-y-z)^2-(x-y+z)^2计算：(x-y-z)^2-(x-y+z)^2计算：(x-y-z)^2-(x-y+z)^2(x-y-z)^2-(x-y+z)^2=[(x-y-z)+(x-y+

计算：(x-y-z)^2-(x-y+z)^2
计算：(x-y-z)^2-(x-y+z)^2

计算：(x-y-z)^2-(x-y+z)^2
(x-y-z)^2-(x-y+z)^2
=[(x-y-z)+(x-y+z)][(x-y-z)-(x-y+z)]
=(x-y-z+x-y+z)(x-y-z-x+y-z)
=(2x-2y)(-2z)
=-4z(x-y);
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：(x-y-z)^2-(x-y+z)^2
= (x-y -z)^2-(x-y +z)^2
= (x-y)²+ z² - 2z (x-y) -(x-y)²- z² + 2z (x-y)
= 4z (x-y)
施主，我看你骨骼清奇，
器宇轩昂,且有慧根,
乃是万中无一的武林奇才.
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：(x-y-z)^2-(x-y+z)^2
= (x-y -z)^2-(x-y +z)^2
= (x-y)²+ z² - 2z (x-y) -(x-y)²- z² + 2z (x-y)
= 4z (x-y)
施主，我看你骨骼清奇，
器宇轩昂,且有慧根,
乃是万中无一的武林奇才.
潜心修习,将来必成大器，
鄙人有个小小的考验请点击在下答案旁的
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解
(x-y-z)²-(x-y+z)²
=[(x-y-z)-(x-y+z)][(x-y-z)+(x-y+z)]
=(-2z)(2x-2y)
=-4z(x-y)

原式=[(x-y-z)+(x-y+z)][(x-y-z)-(x-y+z)]
=(2x-2y)(-2z)
=4yz-4xz

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