(x-y)2(x2+xy+y2)2-(x3+y3)(-x3+y3),其中x=1,y=-1
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/08 13:54:04
(x-y)2(x2+xy+y2)2-(x3+y3)(-x3+y3),其中x=1,y=-1(x-y)2(x2+xy+y2)2-(x3+y3)(-x3+y3),其中x=1,y=-1(x-y)2(x2+xy
(x-y)2(x2+xy+y2)2-(x3+y3)(-x3+y3),其中x=1,y=-1
(x-y)2(x2+xy+y2)2-(x3+y3)(-x3+y3),其中x=1,y=-1
(x-y)2(x2+xy+y2)2-(x3+y3)(-x3+y3),其中x=1,y=-1
(x-y)²(x²+xy+y²)²-(x³+y³)(-x³+y³)
=(x³-y³)² - [-(x³)²+(y³)²]
=(x³)²+(y³)² -2x³y³ +(x³)²-(y³)²
=2(x³)²-2x³y³
=2x³(x³-y³)
把x=1,y=-1代入
2x³(x³-y³)
=2×(1+1)
=2×2
=4
计算(x+y/x-y + 4xy/y2-x2)(x2-9y2)/(x2+2xy-3y2)
4x2-y2/x2-2xy+y2 +(2x-y)/2x2-2xy
(x-y)(x2+xy+y2)
(x+y)(x2-xy+y2)
x2-2xy+y2=4 x2+y2-x-y=6 解不等式x2-2xy+y2=4 x2+y2-x-y=6 解不等式
[2/xy/(1/x+1/y)2+(x2+y2)/(x2+2xy+y2)]*2x/(x-y)
已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2=
因式分解x2-4xy+4y2+x-2y-2
x2-4xy+4y2-x+2y-2因式分解
x2+2xy-3y2+3x+y+2 因式分解
因式分解x2+2+y2-3x-2xy+3y
x2+2xy-8y2+2x+8y因式分解
(x2+y2)2与xy(x+y)2的大小
x2-xy-2y2-x+5y-2
(-x-2y)(x2-2xy+4y2)等于多少
x2-xy-2y2-x+5y-2因式分解
因式分解2y2-xy-3x2-2y+3x
2x2+xy-y2-4x+5y-6 因式分解