x2-xy-2y2-x+5y-2

来源：学生作业帮助网编辑：六六作业网时间：2024/11/08 17:13:55

x2-xy-2y2-x+5y-2x2-xy-2y2-x+5y-2x2-xy-2y2-x+5y-2首先,X^2-XY+2Y^2=(X-2Y)(X+Y)所以,设x^2-xy-2y^2-x+5y-2可分解成

x2-xy-2y2-x+5y-2
x2-xy-2y2-x+5y-2

x2-xy-2y2-x+5y-2
首先,X^2-XY+2Y^2=(X-2Y)(X+Y)
所以,
设x^2-xy-2y^2-x+5y-2可分解成
(X-2Y+A)(X+Y+B)
则展开有X的一次项=A+B=-1
Y的一次项有A-2B=5
连列成方程,解出A=1 B=-2
所以有原式可以分解为:(X-2Y+1)(X+Y-2)

:(X-2Y+1)(X+Y-2)

x2-xy-2y2-x+5y-2 x2-xy-2y2-x+5y-2因式分解 2x2+xy-y2-4x+5y-6 因式分解 X2+xy-12y2-2x+27y+5因式分解已知x2+y2+4x-2y+5=0,求x2+2xy+y2值 4x2-y2/x2-2xy+y2 +(2x-y)/2x2-2xy 计算(x+y/x-y + 4xy/y2-x2)(x2-9y2)/（x2+2xy-3y2）已知x/y=3/5,求 (x2-xy+2y2)/(x2+2xy-y2)的值 x2-2xy+y2=4 x2+y2-x-y=6 解不等式x2-2xy+y2=4 x2+y2-x-y=6 解不等式因式分解：3x2+5xy-2y2+x+9y-4 x2+x-(a2-a) 3x2+4xy-y2 x,y,a后面的2表示平方已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2= 因式分解 2x2+xy-y2-4x+5y-6 x2-y2+a2-b2+2ax+2by 3x2+5xy-2y2+x+9y-4 b4-2b2-82x2+xy-y2-4x+5y-6x2-y2+a2-b2+2ax+2by3x2+5xy-2y2+x+9y-4b4-2b2-8 [2/xy/(1/x+1/y)2+(x2+y2)/(x2+2xy+y2)]*2x/(x-y) 因式分解x2-4xy+4y2+x-2y-2 x2-4xy+4y2-x+2y-2因式分解 x2+2xy-3y2+3x+y+2 因式分解因式分解x2+2+y2-3x-2xy+3y x2+2xy-8y2+2x+8y因式分解